{% else-1 %}
(2 сен 2015, 02:00) (0/0) [0]
Еще кто-то знает?
(2 сен 2015, 01:41) (0/0) [0]
Playtox, Как?
(2 сен 2015, 01:35) (0/0) [0]
mysql_result() expects
parameter 1 to be resource,
boolean given in /home/
u645810184/public_html/inc/
start.php on line 80

Вот код
if(mysql_result(mysql_query
("SELECT COUNT(*) FROM
`kolhoz_lab_o` WHERE
`id_user` = '$ku
[id]'"*,0)==0)
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