(7 окт 2015, 21:53) (0/0)
[0]
Gallardo,
[code]
$image_big = mysql_query("SELECT * FROM `".$prefix."images` WHERE `type` = 'big'"
;
while($count_big = mysql_fetch_array($image_big))
{
echo '<input name="imagebig" value="'.$count_big['name'].'" type="radio" />';
echo '<img src="http://'.$set['url'].'/design/counters/'.$count_big['name'].'.png" alt="" /><br />';
}
$imagebig = htmlspecialchars(trim($_POST['imagebig']));
[/code]
Сижу голову ломаю чего оно так..
$image_big = mysql_query("SELECT * FROM `".$prefix."images` WHERE `type` = 'big'"
;while($count_big = mysql_fetch_array($image_big))
{
echo '<input name="imagebig" value="'.$count_big['name'].'" type="radio" />';
echo '<img src="http://'.$set['url'].'/design/counters/'.$count_big['name'].'.png" alt="" /><br />';
}
$imagebig = htmlspecialchars(trim($_POST['imagebig']));
[/code]
Сижу голову ломаю чего оно так..
(7 окт 2015, 20:45) (0/0)
[0]
Gallardo,
Notice: Undefined variable: imagebig in /www/modules/account.php on line 10
NULL
NULL
(7 окт 2015, 20:13) (0/0)
[0]
Notice: Undefined index: imagebig in ляля/www/modules/account.php on line 95
добавляю
[code]$isset_image = mysql_num_rows(mysql_query("SELECT * FROM `".$prefix."images` WHERE `name` = '".$imagebig."'");
if($isset_image == 0)
{
$error .= 'Текст ...';
}[/code]
Ошибка все равно остается..
$imagebig = htmlspecialchars(trim($_POST['imagebig']));добавляю
[code]$isset_image = mysql_num_rows(mysql_query("SELECT * FROM `".$prefix."images` WHERE `name` = '".$imagebig."'"
);if($isset_image == 0)
{
$error .= 'Текст ...';
}[/code]
Ошибка все равно остается..
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