(23 авг 2014, 23:44) (0/0)
[0]
В php не так давно как исправить ошибку?
$rat_plus = mysql_result(mysql_query("SELECT count (`id`) FROM `reputation` WHERE `id_sait` = '".$id."' AND `type` = 'plus'"
,0);
Warning: mysql_result() expects parameter 1 to be resource, boolean given in /home/u297541962/public_html/infos.php on line 41
$rat_plus = mysql_result(mysql_query("SELECT count (`id`) FROM `reputation` WHERE `id_sait` = '".$id."' AND `type` = 'plus'"
,0);Warning: mysql_result() expects parameter 1 to be resource, boolean given in /home/u297541962/public_html/infos.php on line 41
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