{% else-1 %}
ByUNNAMED * [мошенник] 2.84
(11 ноя 2014, 00:30) (1/0) [1]
<?php
$req = mysql_query("SELECT * FROM `drop_trofei` WHERE `id` = '".$id1."'"*;
$id1 = mysql_fetch_array($req);


echo"<img src='pic/trofei/$id1['колонка'].png' alt=''/>";


?>
  • 1 из 1